An unknown element has a first ionization energy of and an electron affinity of . What is its approx — Periodic Table and Periodicity Chemistry Question
Question
An unknown element has a first ionization energy of $10.4 \text{ eV}$ and an electron affinity of $3.6 \text{ eV}$. What is its approximate electronegativity on the Pauling scale, assuming the standard conversion from the Mulliken scale ($X_P = X_M / 2.8$)?
Answer: B
💡 Solution & Explanation
According to the Mulliken scale, electronegativity is the average of ionization potential and electron affinity: $X_M = \frac{10.4 + 3.6}{2} = 7.0 \text{ eV}$. Converting to the Pauling scale: $X_P = \frac{7.0}{2.8} = 2.5$.
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