What is the calculated Mulliken scale electronegativity of an unknown element if its first ionizatio β Periodic Table and Periodicity Chemistry Question
Question
What is the calculated Mulliken scale electronegativity of an unknown element if its first ionization potential is experimentally determined to be $14.5 \text{ eV/atom}$ and its electron affinity is $3.5 \text{ eV/atom}$?
Answer: 9
π‘ Solution & Explanation
The Mulliken scale defines electronegativity as the simple arithmetic average of the Ionization Potential (IP) and Electron Affinity (EA) when both are expressed in $\text{eV/atom}$. $EN_M = \frac{IP + EA}{2}$. Substituting the values: $EN_M = \frac{14.5 + 3.5}{2} = \frac{18.0}{2} = 9$.
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