What is the positive formal oxidation state of Xenon in the perxenate ion ()? — p Block Elements Chemistry Question

💡 Solution & Explanation

In the $[XeO_6]^{4-}$ ion, let the oxidation state of Xe be $x$. Each oxygen is -2. Thus, $x + 6(-2) = -4 \implies x - 12 = -4 \implies x = +8$.