When 2 moles of orthoboric acid () are heated strongly to red heat to form boron sesquioxide (boric anhydride), how many moles of water () are lost?

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Question

When 2 moles of orthoboric acid ($H_3BO_3$) are heated strongly to red heat to form boron sesquioxide (boric anhydride), how many moles of water ($H_2O$) are lost?

Prashant Kotian · Accepted Answer

Correct answer: 3. Orthoboric acid loses water sequentially upon heating. The overall dehydration reaction at red heat is: . Thus, 3 moles of water are lost per 2 moles of boric acid.

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