When 2 moles of orthoboric acid () are heated strongly to red heat to form boron sesquioxide (boric — p Block Elements Chemistry Question
Question
When 2 moles of orthoboric acid ($H_3BO_3$) are heated strongly to red heat to form boron sesquioxide (boric anhydride), how many moles of water ($H_2O$) are lost?
Answer: 3
💡 Solution & Explanation
Orthoboric acid loses water sequentially upon heating. The overall dehydration reaction at red heat is: $2H_3BO_3 \xrightarrow{\Delta} B_2O_3 + 3H_2O$. Thus, 3 moles of water are lost per 2 moles of boric acid.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes