The half-life of Cobalt-60 is (decay constant ). The decay activity of a sample of Cobalt-60 is appr — Nuclear Chemistry and Radioactivity Chemistry Question

💡 Solution & Explanation

Activity $A = \lambda N$, where $N$ is the total number of atoms. Number of moles = $\frac{2}{60} = \frac{1}{30}$. Total atoms $N = \frac{1}{30} \times 6.023 \times 10^{23} \approx 2 \times 10^{22}$ atoms. Activity $A = (2.5 \times 10^{-7}\text{ min}^{-1}) \times (2 \times 10^{22}\text{ atoms}) = 5 \times 10^{15}\text{ disintegrations per minute (dpm)}$.