Considering standard laboratory conditions, which of the following aqueous solutions having a define — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

Step 1: Relate strength, normality, and equivalent weight. Normality = Strength (in g/L) / Equivalent Weight. Since Strength = 1, Normality = 1 / Equivalent Weight. Step 2: Calculate normality for each. (A) NaOH: E = 40, N = 1/40 = 0.025 N. (B) $H_2SO_4$: E = 49 (98/2), N = 1/49 $\approx 0.0204$ N. (C) HCl: E = 36.5, N = 1/36.5 $\approx 0.0274$ N. (D) $HNO_3$: E = 63, N = 1/63 $\approx 0.0158$ N. Solutions A, B, and C all have normalities > 0.02 N. Solution D is < 0.02 N.