Exactly of Carbon dioxide () gas is passed continuously over a bed of red-hot coke () under standard — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
Exactly $26\text{ mL}$ of Carbon dioxide ($CO_2$) gas is passed continuously over a bed of red-hot coke ($C$) under standard laboratory conditions until the reaction is complete. Calculate the exact volume (in $\text{mL}$) of Carbon monoxide ($CO$) gas evolved in this process.
💡 Solution & Explanation
Step 1: Write the balanced chemical equation for the reduction of $CO_2$ by solid carbon. $CO_2(g) + C(s) \rightarrow 2CO(g)$. Step 2: Apply Gay-Lussac's Law of Gaseous Volumes. The volumes of reacting and produced gases bear a simple whole-number ratio. From the stoichiometry, $1\text{ volume}$ of $CO_2$ gas reacts to produce exactly $2\text{ volumes}$ of $CO$ gas. (The volume of solid carbon is negligible and ignored). Step 3: Calculate the volume of $CO$. Volume of $CO = 2 \times \text{Volume of } CO_2 = 2 \times 26\text{ mL} = 52\text{ mL}$.