Calculate the total number of fundamental electrons present in of pure water (): — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
Calculate the total number of fundamental electrons present in $1.8\text{ g}$ of pure water ($H_2O$):
Answer: B
💡 Solution & Explanation
Step 1: Find moles of water. $n = \frac{1.8\text{ g}}{18\text{ g mol}^{-1}} = 0.1\text{ moles}$. Step 2: Determine electrons per molecule. A single $H_2O$ molecule contains $2(1) + 8 = 10\text{ electrons}$. Step 3: Calculate total electrons. Total electrons $= (\text{moles}) \times (N_A) \times (\text{electrons per molecule}) = 0.1 \times N_A \times 10 = 1 \times N_A = 6.022 \times 10^{23}$ electrons.
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