How many pi () electrons are present in the delocalized aromatic ring system of Naphthalene? — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Naphthalene consists of two fused benzene rings. It has 5 alternating double bonds in its fully conjugated planar system. Each double bond contains 2 pi electrons, yielding $5 \times 2 = 10$ pi electrons, which perfectly follows Huckel's rule $(4n + 2)$ for $n=2$.