The correct IUPAC name of the compound is: — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

When numbering the principal carbon chain, the lowest possible locant set for multiple bonds is selected. Numbering from left to right gives locants 2 and 4. Numbering from right to left gives locants 1 and 3. The set (1, 3) is lower. Thus, the triple bond is at C1 and the double bond is at C3. Alphabetically, 'ene' is written before 'yne', giving Pent-3-en-1-yne.