of acetic acid is mixed with of sodium acetate solution. Assuming for acetic acid, find the exact pH — Ionic Equilibrium Chemistry Question
Question
$50 \text{ mL}$ of $2 \text{ N}$ acetic acid is mixed with $10 \text{ mL}$ of $1 \text{ N}$ sodium acetate solution. Assuming $K_a = 10^{-5}$ for acetic acid, find the exact pH of the resulting solution.
Answer: 4
💡 Solution & Explanation
Milliequivalents (or millimoles, since n-factor=1 for both) of acid = $50 \times 2 = 100 \text{ mmol}$. Millimoles of salt = $10 \times 1 = 10 \text{ mmol}$. Using the Henderson equation: $pH = pK_a + \log\frac{[Salt]}{[Acid]} = 5 + \log\left(\frac{10/V}{100/V}\right) = 5 + \log(0.1) = 5 - 1 = 4$.
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