At , pure water has a hydronium ion concentration of . What is the value of the ionic product of wat — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

In pure water, auto-ionization produces equal concentrations of $[H_3O^+]$ and $[OH^-]$. Therefore, $[H_3O^+] = [OH^-] = 10^{-6.7} \text{ M}$. The ionic product of water $K_w = [H_3O^+][OH^-] = (10^{-6.7})^2 = 10^{-13.4}$.