Calculate the acid dissociation constant, , for a aqueous solution of if its is at . — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

If $pOH = 10$, then $pH = 14 - 10 = 4$. Therefore, $[H^+] = 10^{-4} \text{ M}$. Using the weak acid approximation $[H^+] = \sqrt{K_a \times C}$, we have $10^{-4} = \sqrt{K_a \times 10^{-2}}$. Squaring both sides yields $10^{-8} = K_a \times 10^{-2}$, so $K_a = 10^{-6}$.