Exactly 1 mole of propyne reacts completely with an excess of bromine dissolved in carbon tetrachlor — Hydrocarbons Chemistry Question
Question
Exactly 1 mole of propyne reacts completely with an excess of bromine dissolved in carbon tetrachloride ($Br_2/CCl_4$) in the dark. How many moles of diatomic bromine ($Br_2$) are consumed by the alkyne to form the fully saturated tetrahalogen derivative?
💡 Solution & Explanation
Alkynes possess two $\pi$ -bonds and can undergo two successive electrophilic addition reactions with halogens. One mole of propyne ($CH_3-C\equiv CH$) will react with one mole of $Br_2$ to form a dibromoalkene, which then rapidly reacts with a second mole of $Br_2$ to form 1,1,2,2-tetrabromopropane. Therefore, 2 moles of $Br_2$ are consumed per mole of alkyne.