When n-heptane is passed over a catalyst composed of chromium oxide () supported on alumina () at and 10-20 atm pressure, it undergoes dehydrogenation and cyclization. Which aromatic compound is forme

Question

When n-heptane is passed over a catalyst composed of chromium oxide ($Cr_2O_3$) supported on alumina ($Al_2O_3$) at $600^{\circ}C$ and 10-20 atm pressure, it undergoes dehydrogenation and cyclization. Which aromatic compound is formed as the major product?

Prashant Kotian · Accepted Answer

Correct answer: C. This reaction is called aromatization or catalytic reforming. n-Heptane () contains 7 carbon atoms. It undergoes cyclization to a 6-membered ring and subsequent loss of hydrogen () to form an aromatic ring containing a methyl group, which is toluene (methylbenzene, ). n-Hexane yields benzene.

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