In a highly specialized conductivity cell, it is observed that the measured electrical conductance ( — Electrochemistry Chemistry Question

💡 Solution & Explanation

The fundamental relationship between specific conductance ($\kappa$), conductance ($G$), and the cell constant ($G^* = l/A$) is given by the formula $\kappa = G \times (l/A)$. If it is empirically given that $\kappa = G$, substituting this into the equation yields $G = G \times (l/A)$, which simplifies directly to $l/A = 1\text{ cm}^{-1}$ (unity).