Consider the plot of the reduction potential (y-axis) versus (x-axis) for the half-cell reaction at — Electrochemistry Chemistry Question

💡 Solution & Explanation

According to the Nernst equation for the reduction half-reaction: $E_{red} = E^\circ - \frac{0.0591}{n} \log \frac{1}{[Cu^{2+}]}$. Rearranging gives $E_{red} = E^\circ + \frac{0.0591}{2} \log[Cu^{2+}]$. Comparing this to the equation of a straight line $y = mx + c$, the slope $m$ is $+0.0591 / 2 = 0.0295\text{ V}$.