Determine the total number of atoms present in one complete molecule of the neutral coordination com — Coordination Compounds Chemistry Question
Question
Determine the total number of atoms present in one complete molecule of the neutral coordination complex 'triamminetrinitrito-N-cobalt(III)'.
Answer: 22
💡 Solution & Explanation
The IUPAC name indicates a cobalt(III) center with 3 ammine ($NH_3$) ligands and 3 nitrito-N ($NO_2^-$) ligands. The complex is neutral. The formula is $[Co(NO_2)_3(NH_3)_3]$. Breaking down the atoms: $1$ $Co$ atom + $3 \times (1 \text{ N} + 2 \text{ O}) = 9$ atoms from nitrito + $3 \times (1 \text{ N} + 3 \text{ H}) = 12$ atoms from ammine. Total atoms $= 1 + 9 + 12 = 22$.
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