For a complex stoichiometric reaction , the rate law is . The following data matrix is provided: Exp — Chemical Kinetics Chemistry Question
Question
For a complex stoichiometric reaction $A + B \rightarrow C$, the rate law is $r = k[A]^x [B]^y$. The following data matrix is provided: Exp 1: $[A]=0.1\text{ M}, [B]=0.1\text{ M}, \text{Rate}=0.04$. Exp 2: $[A]=0.2\text{ M}, [B]=0.1\text{ M}, \text{Rate}=0.16$. Exp 3: $[A]=0.1\text{ M}, [B]=0.2\text{ M}, \text{Rate}=0.04$. Calculate the overall integer order of the reaction ($x+y$).
Answer: 2
💡 Solution & Explanation
Dividing Exp 2 by Exp 1: $(0.2/0.1)^x (0.1/0.1)^y = 0.16/0.04 \Rightarrow 2^x = 4 \Rightarrow x=2$. Dividing Exp 3 by Exp 1: $(0.1/0.1)^x (0.2/0.1)^y = 0.04/0.04 \Rightarrow 2^y = 1 \Rightarrow y=0$. The overall order of the reaction is $x + y = 2 + 0 = 2$.
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