Which of the following mathematical integrated rate equations or expressions is/are precisely matche — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

A is correct because $x = kt$ for zero order. B is correct as $kt = \ln(a/(a-x))$ for first order. C is correct: $k = \frac{1}{t}(\frac{1}{a-x} - \frac{1}{a}) = \frac{1}{t}(\frac{a - (a-x)}{a(a-x)}) = \frac{x}{ta(a-x)}$. D is correct because integrating $-\frac{d[A]}{dt} = k[A]^3$ yields $\frac{1}{2(a-x)^2} - \frac{1}{2a^2} = kt$, matching the given form exactly.