A reaction has an equilibrium constant . If the initial concentration of all four species is artific — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

Initially $Q_c = \frac{(1)(1)}{(1)(1)} = 1$. Since $Q_c < K_c$ ($1 < 100$), the reaction proceeds forward. Let $x$ moles react. At equilibrium: $[A] = 1-x$, $[B] = 1-x$, $[C] = 1+x$, $[D] = 1+x$. $K_c = \frac{(1+x)^2}{(1-x)^2} = 100$. Taking the square root: $\frac{1+x}{1-x} = 10 \Rightarrow 1+x = 10 - 10x \Rightarrow 11x = 9 \Rightarrow x = 0.818$. Thus, $[D] = 1 + x = 1.818\text{ M}$.