Exactly of (molar mass ) is completely dissolved in water to make a solution. What is the numerical — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

Active mass for an aqueous solution is its molarity. Moles of $KCl = \frac{0.745}{74.5} = 0.01\text{ mol}$. Volume $= 1000\text{ mL} = 1\text{ L}$. Active mass = $\frac{0.01\text{ mol}}{1\text{ L}} = 0.01\text{ mol L}^{-1}$. Multiplying by $100$ gives $0.01 \times 100 = 1$.