A closed vessel contains of , of , and of at equilibrium. Which of the following active masses is/ar — Chemical Equilibrium Chemistry Question
Question
A $2\text{ L}$ closed vessel contains $2.8\text{ g}$ of $N_2$, $0.4\text{ g}$ of $H_2$, and $3.4\text{ g}$ of $NH_3$ at equilibrium. Which of the following active masses is/are correctly calculated? (Given molar masses: $N=14$, $H=1$)
Answer: A,B,C
💡 Solution & Explanation
Moles of $N_2 = \frac{2.8}{28} = 0.1\text{ mol}$; $[N_2] = \frac{0.1}{2} = 0.05\text{ M}$. Moles of $H_2 = \frac{0.4}{2} = 0.2\text{ mol}$; $[H_2] = \frac{0.2}{2} = 0.10\text{ M}$. Moles of $NH_3 = \frac{3.4}{17} = 0.2\text{ mol}$; $[NH_3] = \frac{0.2}{2} = 0.10\text{ M}$. Options A, B, and C are correct.
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