What is the active mass of of in a two-litre closed flask? (Given molar mass of ) — Chemical Equilibrium Chemistry Question

💡 Solution & Explanation

Active mass is defined as the molar concentration. Number of moles of $HI = \frac{64\text{ g}}{128\text{ g mol}^{-1}} = 0.5\text{ moles}$. Active mass = $\frac{\text{moles}}{\text{Volume in L}} = \frac{0.5}{2} = 0.25\text{ mol L}^{-1}$.