Chemical BondinghardMCQ SINGLE

Given the following thermodynamic data for the formation of : , , , , . What is the heat of formatioChemical Bonding Chemistry Question

Question

Given the following thermodynamic data for the formation of $AX_3(s)$: $\Delta H_{sub} (A) = 100 \text{ kcal/mol}$, $\sum IE_{1,2,3} (A) = 490 \text{ kcal/mol}$, $\Delta H_{diss} (X_2) = 80 \text{ kcal/mol}$, $\Delta H_{eg} (X) = -110 \text{ kcal/mol}$, $\Delta H_{lattice} (AX_3) = -470 \text{ kcal/mol}$. What is the heat of formation ($\Delta H_f$) of $AX_3(s)$?

Answer: A

💡 Solution & Explanation

From the Born-Haber cycle, $\Delta H_f = \Delta H_{sub} + IE + \frac{3}{2} \Delta H_{diss} + 3 \Delta H_{eg} + \Delta H_{lattice}$. Substituting values: $100 + 490 + \frac{3}{2}(80) + 3(-110) - 470 = 590 + 120 - 330 - 470 = -90 \text{ kcal/mol}$.

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full NEET Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry