Determine the absolute total number of nodes (both radial and angular) present in a atomic orbital. — Atomic Structure Chemistry Question

💡 Solution & Explanation

The total number of nodes for any given atomic orbital depends solely on the principal quantum number $n$ and is given by the formula $(n - 1)$. For a $5d_{xy}$ orbital, $n = 5$. Therefore, the total number of nodes is $5 - 1 = 4$. Alternatively, radial nodes ($5-2-1 = 2$) + angular nodes ($l=2$) = $4$.