Using the empirical formula for nuclear radius (where ), calculate the radius of the nucleus of an A — Atomic Structure Chemistry Question
Question
Using the empirical formula for nuclear radius $R = R_0 A^{1/3}$ (where $R_0 = 1.33 \times 10^{-13} \text{ cm}$), calculate the radius of the nucleus of an Aluminum atom ($A = 27$) in cm. If the answer is expressed as $x \times 10^{-13} \text{ cm}$, what is $x$?
Answer: 3.99
💡 Solution & Explanation
The radius $R = R_0 A^{1/3} = 1.33 \times 10^{-13} \times (27)^{1/3} = 1.33 \times 10^{-13} \times 3 = 3.99 \times 10^{-13} \text{ cm}$. Thus, $x = 3.99$. [43, 44]
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