To completely reduce one mole of nitrobenzene () to aniline () using an active metal and acid mixtur — Aromatic Hydrocarbons Chemistry Question
Question
To completely reduce one mole of nitrobenzene ($C_6H_5NO_2$) to aniline ($C_6H_5NH_2$) using an active metal and acid mixture (e.g., $Sn/HCl$), how many moles of nascent hydrogen $[H]$ are theoretically required according to the balanced stoichiometry?
💡 Solution & Explanation
The overall reduction of nitrobenzene to aniline requires the complete removal of 2 oxygen atoms (as 2 molecules of water, consuming 4 hydrogens) and the addition of 2 hydrogen atoms to the nitrogen atom to form the amine. Therefore, $4 + 2 = 6$ moles of nascent hydrogen $[H]$ are required. The stoichiometric reaction is: $Ph-NO_2 + 6[H] \rightarrow Ph-NH_2 + 2H_2O$.