When an excess of benzene reacts with dichloromethane () in the presence of anhydrous , diphenylmeth — Aromatic Hydrocarbons Chemistry Question

💡 Solution & Explanation

Dichloromethane has two leaving groups (chlorine atoms). Under Friedel-Crafts conditions, it sequentially alkylates two separate benzene rings. The resulting product is diphenylmethane ($Ph-CH_2-Ph$), which contains exactly 2 benzene rings joined by a methylene bridge.