When one single mole of pure liquid ethanol () is correctly meticulously heavily reacted completely — Haloalkanes and Haloarenes Chemistry Question
Question
When one single mole of pure liquid ethanol ($CH_3CH_2OH$) is correctly meticulously heavily reacted completely strictly with a warm, strongly alkaline solution of pure iodine to reliably cleanly form a yellow precipitate, exactly how many moles of $I_2$ are strictly totally perfectly stoichiometrically consumed?
💡 Solution & Explanation
The explicit iodoform reaction sequence for ethanol properly requires two distinct phases: an initial oxidation to acetaldehyde, reliably consuming precisely $1$ mole of $I_2$, flawlessly followed accurately securely by exhaustive alpha-halogenation safely cleanly consuming exactly $3$ completely more moles of $I_2$. The completely explicitly perfectly balanced overall stoichiometric chemical equation accurately beautifully is: $CH_3CH_2OH + 4I_2 + 6NaOH \rightarrow CHI_3 + HCOONa + 5NaI + 5H_2O$. Thus, $4$ moles are completely perfectly uniquely consumed.