An organic chemist evaluates the relative reactivities of the following four halomethanes with a sta — Haloalkanes and Haloarenes Chemistry Question
Question
An organic chemist evaluates the relative $S_N2$ reactivities of the following four halomethanes with a standard strong nucleophile: (I) $CH_3I$, (II) $CH_3Br$, (III) $CH_3Cl$, (IV) $CH_3F$. If these specific compounds are rigidly arranged in strictly descending order of their reaction rates, what is the precise numerical position (1, 2, 3, or 4) occupied by $CH_3Cl$?
💡 Solution & Explanation
In an $S_N2$ reaction on identical carbon skeletons, the rate is exclusively determined by the leaving group ability of the halogen. A good leaving group is the weak conjugate base of a strong acid. The acidity order is $HI > HBr > HCl > HF$. Therefore, the leaving group ability follows the sequence: $I^- > Br^- > Cl^- > F^-$. The reactivity of the halomethanes decreases in the exact same sequence: $CH_3I > CH_3Br > CH_3Cl > CH_3F$. Thus, $CH_3Cl$ occupies the 3rd position in this descending series.