Liquid n-hexane and liquid n-heptane mix to form a practically ideal solution. If of pure n-hexane i — Solutions and Colligative Properties Chemistry Question
Question
Liquid n-hexane and liquid n-heptane mix to form a practically ideal solution. If $40\text{ mL}$ of pure n-hexane is gently mixed with exactly $60\text{ mL}$ of pure n-heptane at a constant temperature, what will be the exact total final volume of the resulting mixture in $\text{mL}$?
Answer: 100
💡 Solution & Explanation
Because n-hexane and n-heptane form an ideal solution, the change in volume upon mixing ($\Delta V_{mix}$) is exactly zero. Therefore, the total volume is perfectly additive: $V_{total} = V_{hexane} + V_{heptane} = 40\text{ mL} + 60\text{ mL} = 100\text{ mL}$.
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