A laboratory solution was prepared by adding of pure isopropyl alcohol to pure water until the final — Solutions and Colligative Properties Chemistry Question
Question
A laboratory solution was prepared by adding $125\text{ cm}^3$ of pure isopropyl alcohol to pure water until the final uniform volume of the solution became exactly $175\text{ cm}^3$. Determine the volume percent ($\%\, v/V$) of isopropyl alcohol in this solution. (Round your answer to the nearest integer).
Answer: 71
💡 Solution & Explanation
Volume percent ($\%\, v/V$) is defined as $\frac{\text{Volume of solute}}{\text{Total volume of solution}} \times 100$. Here, volume of solute = $125\text{ cm}^3$, and total volume = $175\text{ cm}^3$. Therefore, $\%\, v/V = \frac{125}{175} \times 100 = 71.42\%$. Rounded to the nearest integer, it is $71$.
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