A solid mixture of (Compound A) and (Compound B) required equal volumes of 0.1 M (in acidic medium) — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Let moles of A = $a$ and B = $b$. For $KMnO_4$ titration: A ($n=2$), B ($n=4$ because 2 oxalate groups). Total equivalents = $2a + 4b = 0.1 \times V \times 5 = 0.5V$. For NaOH titration: A ($n=0$, neutral salt), B ($n=3$ because 3 acidic protons). Total equivalents = $3b = 0.1 \times V \times 1 = 0.1V$. Therefore, $V = 30b$. Substitute $V$ in the first equation: $2a + 4b = 0.5(30b) = 15b \Rightarrow 2a = 11b \Rightarrow a/b = 11/2 = 5.5 : 1$.