100 mL of an solution was diluted to 400 mL. 20 mL of this diluted solution required 10 mL of 0.1 M — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Milli-equivalents of $KMnO_4 = M \times n \times V = 0.1 \times 5 \times 10 = 5$ meq. Thus, 20 mL of diluted $H_2O_2$ contains 5 meq. Normality of diluted $H_2O_2 = 5 / 20 = 0.25 N$. The solution was diluted from 100 mL to 400 mL (dilution factor of 4), so the original normality = $0.25 \times 4 = 1.0 N$. Volume strength = $5.6 \times N = 5.6 \times 1.0 = 5.6 V$.