Consider the redox reaction in acidic medium: When this equation is perfectly balanced with the smal — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Oxidation: $H_2O_2 \rightarrow O_2 + 2H^+ + 2e^-$ (multiply by 5). Reduction: $MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$ (multiply by 2). Combining gives $2MnO_4^- + 16H^+ + 5H_2O_2 \rightarrow 2Mn^{2+} + 8H_2O + 5O_2 + 10H^+$. Cancelling $H^+$ on both sides yields a net of $6H^+$ on the reactant side.