What volume (in mL) of 0.1 M solution is required to completely oxidize 100 mL of 0.5 M (ferrous oxa — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Using the Law of Equivalence: $M_1V_1n_1 = M_2V_2n_2$. For $KMnO_4$ in acidic medium, $n_1 = 5$. For $FeC_2O_4$, both $Fe^{2+}$ and $C_2O_4^{2-}$ oxidize. $Fe^{2+} \rightarrow Fe^{3+} + 1e^-$, and $C_2O_4^{2-} \rightarrow 2CO_2 + 2e^-$. Total n-factor $n_2 = 1 + 2 = 3$. Substituting: $0.1 \times V \times 5 = 0.5 \times 100 \times 3 \Rightarrow 0.5 V = 150 \Rightarrow V = 300$ mL.