The equivalent mass of is exactly half its molecular mass when it is converted to which of the follo — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Equivalent mass = (Molar Mass) / n-factor. For E = M/2, the n-factor must be 2. In $MnSO_4$, Mn is in a +2 oxidation state. In $MnO_2$, Mn is in a +4 oxidation state. The change in oxidation state is $ | 4 - 2 | = 2$.