In Carbon suboxide (), the mathematically calculated average oxidation state and the actual structur — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Let the average O.S. of C be $x$. $3x + 2(-2) = 0 \Rightarrow x = +4/3$. Structurally, carbon suboxide is linear ($O=C=C=C=O$). The terminal carbons are attached to oxygen (+2), while the central carbon is attached only to other carbons (0).