The reaction is fundamentally an example of: — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

In this reaction, Barium remains +2 and Oxygen remains -1 (as it is a peroxide in both $BaO_2$ and $H_2O_2$). Sulphur remains +6. Since no element changes its oxidation state, it is a simple non-redox double displacement reaction.