Practical Organic Chemistry and PurificationhardNUMERICAL

of an anhydrous organic acid gave on complete combustion of and of . Calculate the percentage of CarPractical Organic Chemistry and Purification Chemistry Question

Question

$0.20\ \text{g}$ of an anhydrous organic acid gave on complete combustion $0.44\ \text{g}$ of $CO_2$ and $0.18\ \text{g}$ of $H_2O$. Calculate the percentage of Carbon in the compound. (Atomic masses: $C=12$, $O=16$, $H=1$)

Answer: 60

💡 Solution & Explanation

Using Liebig's method formula for percentage of carbon: $\%C = \frac{12}{44} \times \frac{\text{Mass of } CO_2}{\text{Mass of compound}} \times 100$. Substituting the values: $\%C = \frac{12}{44} \times \frac{0.44}{0.20} \times 100 = 12 \times \frac{0.01}{0.20} \times 100 = \frac{12}{20} \times 100 = 60\%$.

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