In Dumas' method, of an organic compound yields of nitrogen gas collected at standard temperature an β Practical Organic Chemistry and Purification Chemistry Question
Question
In Dumas' method, $0.14\ \text{g}$ of an organic compound yields $22.4\ \text{mL}$ of nitrogen gas collected at standard temperature and pressure (STP). Calculate the percentage of nitrogen in the compound. (Assume molar volume of gas at STP = $22400\ \text{mL}$)
Answer: 20
π‘ Solution & Explanation
In Dumas' method, the mass of nitrogen is derived from its volume at STP. 22400 mL of $N_2$ weighs 28 g. Therefore, 22.4 mL of $N_2$ weighs $\frac{28}{22400} \times 22.4 = 0.028\ \text{g}$. The percentage of Nitrogen = $\frac{0.028}{0.14} \times 100 = 20\%$.
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