Based strictly on the differences in Pauling electronegativity values, which of the following pairs — Periodic Table and Periodicity Chemistry Question
Question
Based strictly on the differences in Pauling electronegativity values, which of the following pairs correctly identifies the LEAST and MOST polar covalent bonds respectively among $C-I, N-O, C-F,$ and $P-F$?
Answer: B
💡 Solution & Explanation
Bond polarity is directly proportional to the electronegativity difference ($\Delta EN$). Approximate Pauling values: F(4.0), O(3.5), N(3.0), Cl(3.0), C(2.5), S(2.5), I(2.5), P(2.1). Differences: $C-I$ ($2.5-2.5=0$), $N-O$ ($3.5-3.0=0.5$), $C-F$ ($4.0-2.5=1.5$), $P-F$ ($4.0-2.1=1.9$). $C-I$ is the least polar (almost non-polar) and $P-F$ is the most polar.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes