The first electron gain enthalpy () of an Oxygen atom is and its second electron gain enthalpy () is — Periodic Table and Periodicity Chemistry Question
Question
The first electron gain enthalpy ($\Delta_{eg}H_1$) of an Oxygen atom is $-141 \text{ kJ/mol}$ and its second electron gain enthalpy ($\Delta_{eg}H_2$) is $+744 \text{ kJ/mol}$. What is the net overall enthalpy change (in $\text{kJ/mol}$) for the full double-reduction process $O_{(g)} + 2e^- \rightarrow O^{2-}_{(g)}$?
💡 Solution & Explanation
By Hess's Law, the total enthalpy change for a multi-step process is the algebraic sum of the individual step enthalpies. Thus, the net enthalpy change for the addition of two electrons is $\Delta H_{\text{net}} = \Delta_{eg}H_1 + \Delta_{eg}H_2 = -141 + 744 = +603 \text{ kJ/mol}$.