What is the total sum of (sigma) bonds and (pi) bonds present in a single, intact molecule of borazi — p Block Elements Chemistry Question

💡 Solution & Explanation

Borazine has a planar hexagonal ring structure similar to benzene. It contains 3 B-N single bonds, 3 B=N double bonds (which give 6 $\sigma$ and 3 $\pi$ bonds in the ring), plus 3 B-H $\sigma$ bonds and 3 N-H $\sigma$ bonds. Total = 12 $\sigma$ bonds + 3 $\pi$ bonds = 15 bonds.