For the generic chemical reaction , exactly of reactant A and of reactant B are combined in a reacto — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

Step 1: Identify the limiting reagent. Divide given moles by stoichiometric coefficients. For A: $15 / 3 = 5$. For B: $12 / 2 = 6$. Because $5 < 6$, reactant A is the limiting reagent (Statement A is True). Step 2: Calculate product C formed. $3\text{ moles}$ of A yield $4\text{ moles}$ of C. So, $15\text{ moles}$ of A yield $(4/3) \times 15 = 20\text{ moles}$ of C (Statement C is True). Step 3: Calculate B consumed and excess. $3\text{ moles}$ of A consume $2\text{ moles}$ of B. So, $15\text{ moles}$ of A consume $(2/3) \times 15 = 10\text{ moles}$ of B. Excess B = Initial - Consumed = $12 - 10 = 2\text{ moles}$ remaining (Statement B is True).