The total charge present on exactly of ions is (where represents the magnitude of charge on and is A — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
The total charge present on exactly $1\text{ gram-ion}$ of $Al^{3+}$ ions is (where $e$ represents the magnitude of charge on $1\text{ electron}$ and $N_A$ is Avogadro's number):
Answer: D
💡 Solution & Explanation
Step 1: Understand the term "gram-ion". $1\text{ gram-ion}$ means exactly $1\text{ mole}$ of ions. Step 2: One single $Al^{3+}$ ion carries a charge of $+3e$. Step 3: Therefore, $1\text{ mole}$ ($N_A$ ions) of $Al^{3+}$ will carry a total charge of $3 \times N_A \times e\text{ coulombs}$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes