For a symmetrical molecule with an ODD number ('') of chiral centers, the central carbon is stereoch β Isomerism and Stereochemistry Chemistry Question
Question
For a symmetrical molecule with an ODD number ('$n$') of chiral centers, the central carbon is stereochemically referred to as a pseudo-chiral center. What is the correct mathematical formula used to determine the TOTAL overall number of stereoisomers for such a molecule?
Answer: C
π‘ Solution & Explanation
For symmetrical molecules possessing an odd number of chiral centers, the formula for the total number of stereoisomers is exactly $2^{n-1}$. This mathematically represents the sum of the optically active forms ($2^{n-1} - 2^{(n-1)/2}$) and the optically inactive meso forms ($2^{(n-1)/2}$).
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