If 6 grams of pure (+)-2-butanol is physically mixed with 2 grams of pure (-)-2-butanol, what is the — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

Total mass of the mixture is $6 + 2 = 8 \text{ g}$. The enantiomeric excess (ee) or optical purity is the difference in mass of the enantiomers divided by the total mass: $ee = \frac{6 - 2}{6 + 2} \times 100 = \frac{4}{8} \times 100 = 50\%$.