What is the minimum number of hybridized carbon atoms that must be attached to different substituent groups in a cycloalkane for the ring to successfully exhibit geometrical isomerism?

Question

What is the minimum number of $sp^3$ hybridized carbon atoms that must be attached to different substituent groups in a cycloalkane for the ring to successfully exhibit geometrical isomerism?

Prashant Kotian · Accepted Answer

Correct answer: 2. Cycloalkanes show Geometrical Isomerism (GI) due to the restricted rotation around the rigid single bonds of the ring. For GI to exist, a minimum of two separate hybridized carbons in the ring must each be bonded to two different atoms or groups, allowing for 'cis' (same side) or 'trans' (opposite side) spatial arrangements.

💡 Solution & Explanation

Practice 22,000+ questions like this